i read in Theory of Poker that, when figuring pot odds, if you bet as a semi-bluff or block, you need to calculate the raise back in addition to your original bet. maybe an example will clarify...

Absolute Poker No-Limit Hold'em, $0.25 BB (5 handed) Absolute-Poker Converter Tool from FlopTurnRiver.com (Format: FlopTurnRiver)

SB ($13)
BB ($47.78)
UTG ($18.07)
Hero ($49.98)
Button ($18.40)

Preflop: Hero is MP with K, A.
1 fold, Hero raises to $1, 1 fold, SB calls $0.90, 1 fold.

Flop: ($2.25) 6, T, J (2 players)
SB checks, Hero bets $1.5, SB calls $1.50.

Turn: ($5.25) 3 (2 players)
SB checks, Hero bets $4, SB raises to $8, Hero calls $4.

River: ($21.25) 5 (2 players)
SB bets 2.50 , Hero calls $2.50.

Final Pot: $23.75

question is not about how the hand was played, but how to calculate the odds on the minraise. i throw out the $4 bet, and get minraised another $4. do i figure it as $4 to call into now $17, or 4:1 since my original $4 is gone? or, am i understanding Sklansky correctly when he says i need to figure it as $8 (my $4 + the raise of $4) into $17...making this a clear fold?