What you are saying makes literally no sense.

" If he has a pair, you have 7 outs"
I have 8 outs to the straights as well as 3 outs to a pair of aces 8 + 3 = 11

If I have 0% fold equity as you guys are claiming, then my shoving is the same as just putting him all in. If this was the case i would be risking $.20 to win $.51 therefore i would need (.2)/(.51+.2) x 100 = 28.17% equity.

even if his range was only two pair i would have a profitable push :

Hand 0: 30.535% 29.33% 01.20% 7840 322.00 { Ad9s }
Hand 1: 69.465% 68.26% 01.20% 18246 322.00 { QTs+, JTs, QTo+, JTo }

Please this is not a spot to get away from, shoving is profitable, i am only asking if it is the most profitable way to handle this type of situation.