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					  Originally Posted by  Cocco_Bill
					
				 
				off topic! 
 
What happens if v^2 > c^2 were possible? We get imaginary time! Did you know that Stephen Hawkins created a mathematical model which eliminates the need of a singularity during the creation of universe by using imaginary time? 
			
		 
	 
 Yes I had heard of Stephen Hawking's ideas on that topic. Very interesting stuff to say the least. 
 
If v^2 > c^2 were possible, then the denominator becomes a complex number and the result would be a number in the imaginary plane. But who is to say the Lorentz Transformation Equation either a) holds for numbers not in the domain of reals or b) holds for any numbers period? 
 
Of course I believe b) not to be an issue, but a) definitely is not resolved. 
 
I just don't see how v could be bigger than c. That is of course unless the Lorentz Transformation is brutally wrong. But if you look at the LTE and take the limit of it as v->c.... 
 
lim(v->c) 1/1-v^2/c^2 = 0 (really it's indeterminite) therefore the limit of the whole LTE is 0 as v goes to c. What does this mean? The amazing implication is that to an observer in frame S ("still" ref frame), something travelling at c would appear to take no time to get anywhere, or be anywhere, but from someone going at c in ref frame S', infinite time would pass in S. 
 
All very interesting stuff, and definitely something I plan to do a lot of research on as I work towards graduate studies in Astronomy/Physics. 2nd year starts in two weeks!
					 
				 
				
			 
			 
		  
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