Quote Originally Posted by OngBonga View Post
Often, when my housemates get back from work, they open the front door (inwards), which in turn causes a shift in the air pressure in the house, which travels upstairs and causes my bedroom door to slowly creak open. Is this similar to what's described here?
Yes (assuming your door opens inward). What causes your door to push open is a pressure differential (different in one place than another), which is caused by the collision of air molecules on one side of your door delivering more net force than the the collision of air molecules on the other side of your door.

There is a shock wave (a weak one, but I still think it's the right word) as the pressure increase from the door opening passes through the interior volume of the home. As with all shock waves, there is a difference in pressure and density across the shock wave. So as the wave passes over things (which are thick compared to the width of the shock wave), there is a moment where the surface experiences a different pressure on one side than the other. This results in a net force being applied and F = ma, so where there's a net F, there's a net a.

This shock wave was caused in the first moments of opening the door before the thickness of the door has cleared the door frame. This is the part of the door opening which slightly compresses the air in the path of the door. Once the thickness of the door clears the frame, the increased pressure on the inside of the door has an easy path around to the decreased pressure on the other side of the door.

The result is a pulse which travels in the same manner as a sound wave. I think that it could be perfectly described as a subsonic pulse, or a "sound" wave that is of too low frequency to be heard by human ears.

Experiment by having him open the door more and less quickly than usual. Change how wide the gap is when your door is ajar.

I'm guessing that the effect is most pronounced when he opens the door quickly and when your door is nearly (but not quite) closed.