Can anyone help with this?

A 420 g block is at rest on a horizontal surface. The coefficient of static friction between the block and the surface is 0.800, and the coefficient of kinetic friction is 0.230. A force of magnitude P pushes the block forward and downward. Assume the force is applied at an angle of 23.0° below the horizontal.

(a) Assuming P is large enough to make the block move, find the acceleration of the block as a function of P. (Use P as necessary and round numbers to the third decimal place.)
a(P) = ?

(b) If P = 4.12 N, find the acceleration and the friction force exerted on the block.

(c) If P = 8.24 N, find the acceleration and the friction force exerted on the block.

For A I have to set the net force equal to m*a right? If so then I got n = mg + Psin(-23) for the vertical forces and for the horizontal forces I'm not sure if I'm supposed to use both the force of static friction and the force of kinetic friction in my equation or just one or the other.