well about the AX. What your saying from a probability point of view is correct.

But think about it, how many aces you got remaining in the deck? Three. So in reality, he can only have one of these three aces to have AX.

I think for me, there's alot of confusion between probability of being dealt, and ACTUAL physical hands available.

Again, i see all these numbers, especially with the number of hands that dominate AJ for example. Maths will tell you 12 ways for this and 9 ways for that. But in reality, you only got 3 remaining aces, and the pairs KK, KK, QQ, QQ, and the one JJ.

This is just the way i'm thinking. if someone can explain it to me, then i welcome it.