
Originally Posted by
Lukie
I sincerely appreciate the effort, but this thinking is severely flawed because pokerstove cannot weight ranges, which is extremely important in this spot.
Seems like we need to do some math.
Let's assume the following:
You think that he has either an overpair or overcards. You also think that if he has anything other than that, he will fold to a shove.
Then EV = P(call)*(P(op)*EV(op) + P(oc)*EV(oc)) + P(fold)*EV(fold)
Your read on him might be that 90% of the time he will have overcards (AK/AQ) and 10% of the time an overpair. You also think that sometimes he is on a complete bluff and will fold to a shove, perhaps 5% of the time.
90% of the time your chance of winning is approximately 54%
10% of the time your chance of winning is approximately 20%
P(fold) = 0.05
P(call) = 0.95
EV(op) = 0.2*(6696+800) - 0.8*(6696-800) = -3217.6
EV(oc) = 0.54*(6696+800) - 0.46*(6696-800) = 1335.68
EV(fold) = 3800
EV = 0.95*( //he calls...
0.10*(0.2*(6696+800) - 0.8*(6696-800)) + //...with overpair
0.9*(0.54*(6696+800) - 0.46*(6696-800))) + //...with overcards
0.05*3800 //he folds
=
1026 usd
Clearly EV+ with those reads at least.
But that doesn't answer your question (I don't know your read exactly). What we actually want to know is: what does the likelyhood P(oc) of him having overcards have to be for the call to be EV+?
We need to know when:
P(call)*(P(op)*EV(op) + P(oc)*EV(oc)) + P(fold)*EV(fold) > 0
First lets find out when:
P(call)*(P(op)*EV(op) + P(oc)*EV(oc)) + P(fold)*EV(fold) = 0
Since we assume that if he calls, then P(op) + P(oc) = 1, we get:
P(call)*(EV(op) - P(oc)*EV(op) + P(oc)*EV(oc)) + P(fold)*EV(fold) = 0
EV(op) - P(oc)*EV(op) + P(oc)*EV(oc) = - P(fold)*EV(fold)/P(call)
-P(oc)*EV(op) + P(oc)*EV(oc) = -P(fold)*EV(fold)/P(call) - EV(op)
P(oc)*EV(op) - P(oc)*EV(oc) = P(fold)*EV(fold)/P(call) + EV(op)
P(oc)*(EV(op)-EV(oc)) = P(fold)*EV(fold)/P(call) + EV(op)
Finally:
P(oc) = (P(fold)*EV(fold)/P(call) + EV(op))/(EV(op)-EV(oc))
P(oc) = (190/0.95 - 3217.6) / (-3217.6-1335.68);
P(oc) = -3017.6 / -4553.28 = 0.663
So my answer to your initial question is: If you think the likelyhood of him having overcards is more than 66.3% and you think he will fold to a shove 5% of the time, then throw your chips in.
Class dismissed.