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Optimal HUNL for Dummies:
look what Mason bumped:
http://forumserver.twoplustwo.com/sh...fpart=all&vc=1
I missed this the first time through.
 Originally Posted by Lee Jones
Heads-up Jam/Fold - SAGE
Copyright © 2005 by James Kittock and Lee Jones
Optimal Top % and Cutoff Hands
SB (jam) BB (call)
R | Top % | Cutoff Hand | Top % | Cutoff Hand | Delta SB (in BB units)
1 89% 62s 100% 32o 0.010
2 79% 64s 89% 62s 0.051
3 74% 95o 70% 75s 0.061
4 71% T4o 60% J5o 0.047
5 68% 96o 53% 97s 0.026
6 64% 76s 48% Q2s 0.002
7 61% T4s 42% Q7o -0.018
8 58% J2s 39% K2s -0.042
9 55% 98o 36% 33 -0.063
===============
The “Sit And Go Endgame” System (SAGE)
Copyright © 2005 by James Kittock and Lee Jones
1. SAGE: Computing a Power Index (PI)
a. The “power number” of each card is its rank. J=11, Q=12, K=13, A=15 (don't forget the ace is 15!)
b. Take the power number for your higher card and double it.
c. Add the power number of your lower card.
d. If it's a pocket pair, add 22.
e. If they're suited, add 2.
f. The sum is the Power Index (PI) of your hand.
2. SAGE: Using the PI
a. Compute the ratio (R) of the shortest stack to the big blind.
b. Look up the necessary PI for that value of R.
c. If the PI of your hand is greater than or equal to that value, then jam (if you're the button/small-blind) or call (if you're the big blind).
3. The SAGE Numbers
R Jam (SB) Call (BB)
====================
1 17 any
2 21 17
3 22 24
4 23 26
5 24 28
6 25 29
7 26 30
4. SAGE Example 1
a. Blinds are 500/1000. After the blinds are taken, the SB has 5635 chips and the BB has 2865 chips.
b. The SB has pocket 3's. PI = (2 x 3) + 3 + 22 = 31
c. BB has J4s. PI = (2 x 11) + 4 + 2 = 28
d. The value of R is the smaller stack (2865) divided by 1000 ˜ 3.
e. Looking at the table, the SB should jam, and the BB should call, since both have PIs higher than the respective entry in the table (22 for the SB and 24 for the BB).
5. SAGE Example 2
a. Same circumstance, but the blinds are 200 and 400.
b. Now R is 2865 divided by 400 ˜ 7.
c. The SB should still jam (his PI of 31 is greater than the necessary 26).
d. If the SB jams, the BB should now fold, since his PI (28) is smaller than the corresponding entry (30).
Its kinda cute.
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