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I touched on it here:
http://www.flopturnriver.com/phpBB2/...315582e7afd5d2
The chance of loosing 8 in a row is 0.505^8 = 0.0039, so that is right.
Now to find the chance of one string of 8 in a row in a set of hands. First, understand that if we play 100 hands in a row there are 92 sequences of 8 hands.
1, 2, ... 8
2, 3, ... 9
...
92, 93, ... 100
We can treat these as independent because we don't know any of the sequences. Obviously, if the sequence starting at 5 is 10110010, then the chance of the sequence starting at 6 being 00000000 is zero. But, since we don't know 5, the chance of 6 being all loses is still .4%.
Since the chance of losing 8 in a row is .4, the chance of not losing 8 in a row is 99.6. The chance of in 200 hands not loosing 8 in a row is 99.6^193 = 44.9%.
You will play more than 200 hands, you will go busto. The martingale system sucks outside of theoretical discussion.
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