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 edit : less than mediocre puzzle
After work , this guy gets on a Tube train in London . He normally meets his g/f at this tube station ,and they travel together and walk home together . But she was delayed this day , at the newspaper stand .
He gets on the tube without her and gets off at his home station , and walks home the usual way. normal pace etc.
The delayed g/f gets the later tube (same station) , and gets off at their home station , exactly the same a her b/f , and walks the same route as her b/f . She doesn't overtake her b/f , nor deviate from the normal route /pace etc .
When the b/f gets home, he finds the g/f there already . Alive and well, reading the previously purchased newspaper.
How was this possible ?
 Originally Posted by a500lbgorilla
If you've heard of this riddle before, you're honor bound to say spoilers before you give the answer.
edited to clarify there are only 2 tube stations involed
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